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Ierofanga [76]
3 years ago
8

Distance between (-5,-6) and (5,6)

Mathematics
1 answer:
DENIUS [597]3 years ago
5 0

Answer:

2\sqrt{61}

Step-by-step explanation:

Look here!

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Right triangles 1,2 and 3 are given to its all their angle measures and approximate side lengths
Ede4ka [16]

Answer:

5.4 units

Step-by-step explanation:

From the figure ,it's clear that   sin(50) = PQ/7

Then

PQ = 7×sin(50) = 5.362311101833

Therefore the approximate length of PQ I saw 5.4

6 0
2 years ago
Ricardo paid $15 for 4 pounds of almonds. At this price, how much would he pay for 10 pounds of
vampirchik [111]
I know the answer is 37.5
4 0
3 years ago
Select whether the equation has a solution or not.<br> √x = 7
Ierofanga [76]

Answer:

x = 49

The equation does have a solution

Step-by-step explanation:

The sqrt of x = 7, does have a solution. Simply remove the radical, and raise each side by the index of the radical.

In more basic terms, what number has the sqrt of 7? 7^2 is equal to 49!

6 0
4 years ago
The vertex angle of an isosceles triangle is 20° less than the sum of the base angles. Which system of equations can be used to
WINSTONCH [101]

The answer to the above question can be explained as under -

We know that, the sum of angles of triangle is 180°.

So, vertex angle plus base angles are equal are equal to 180°.

Let the vertex angle be represented by "v" and base angles be represented by "b".

Thus,  v + b + b = 180°

So,  v + 2b = 180°

Next, the question says, the vertex angle is 20° less than the sum of base angles.

Thus, 2b - 20° = v

<u>Thus, we can conclude that the correct option is A) v + 2b = 180°, 2b - 20° = v</u>

6 0
3 years ago
Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

#SPJ1

8 0
2 years ago
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