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Bad White [126]
3 years ago
11

What is 1/3 divided by 1/18

Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0

Answer: 6

Step-by-step explanation:

Not sure how to explain this answer but I’m pretty sure it’s 6 so yeah...

denpristay [2]3 years ago
6 0

Answer:

6

Step-by-step explanation:

1/3 ÷ 1/18

1/3 × 18/1       Keep Change Flip

18/3=6

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Connie bought 172 tulip bulbs. She wants to plant an equal number of bulbs in each of 4 flower beds. How many bulbs should Conni
Montano1993 [528]
She should plant 43 tulip bulbs in each bed.
8 0
3 years ago
Please help. How do I solve this?
LuckyWell [14K]
I believe the answer could be c but i’m not an expert on this subject- you’d have to fact check it with someone else on here
5 0
3 years ago
Find the exponential function P(t)=P0a^t where P(2)=5 and P(4)=10
asambeis [7]

Answer:

P(t)=\frac{5}{2} \cdot (\sqrt{2})^t

Step-by-step explanation:

P(2)=5 meants when t=2, that the value for P(t) is 5.

So this gives us this equation:

5=P_0 \cdot a^2

P(4)=10 meants when t=4, that the value for P(t) is 10.

So this gives us this equation:

10=P_0 \cdot a^4

So I take equation 2 and divide it be equation 1 I get:

\frac{10}{5}=\frac{P_0 \cdot a_4}{P_0 \cdot a_2}

Simplifying:

2=a^2

Since the base for an exponential function can't be negative then a=\sqrt{2}.

So plugging into one of my equations I began with gives me an equation to solve for the initial value,P_0:

5=P_0 \cdot (\sqrt{2})^2

5=P_0 \cdot 2

Divide both sides by 2:

\frac{5}{2}=P_0

The function is:

P(t)=\frac{5}{2} \cdot (\sqrt{2})^t

7 0
4 years ago
Adrian cuts a block of wood as shown. What is the volume of the block of wood?
kozerog [31]

Answer:

432

Step-by-step explanation:

Volume of cuboid:

12 x 4.5 x 5.5 = 297

volume of traingular prism:

(12x5)/2 x 4.5 =135

add them together:

135+297 =432

hope this helps!

6 0
3 years ago
Sam's car traveled 120 miles on 9 gallons of gasoline. Which fraction expresses the ratio of miles to gallons?
gogolik [260]
Miles to gallons=120:9=40:3
6 0
3 years ago
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