Answer:
A(0,10)
Step-by-step explanation:
Given the 4 inequalities:
s ≥ 12 - 0.5t (1)
s ≥ 10 -t (2)
s ≤ 20-t (3)
s ≥ 0
t ≥ 0
Let analyse all 4 possible answer:
Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong
We do not choose A
Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True
Let substitute this point into (2) we have: 20 ≥ 10 - 0 True
Let substitute this point into (3) we have: 20 ≤ 20 - 0 True
We choose B as the vertex
Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True
Let substitute this point into (2) we have: 16 ≥ 10 - 4 True
Let substitute this point into (3) we have: 16 ≤ 20 - 4 True
We choose C as the vertex
Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True
Let substitute this point into (2) we have: 4 ≥ 10 - 16 True
Let substitute this point into (3) we have: 4 ≤ 20 - 16 True
We choose B as the vertex
Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.
