<u>Answer:</u>
Below!
<u>Step-by step explanation:</u>
<u>We know that:</u>
<u>Solution of Question A:</u>
<u>Percent of children: Total children/Total attendance</u>
- => 400/1500
- => 4/15
- => 0.27 (Rounded to nearest hundredth)
- => 0.27 x 100
- => 27%
<u>Hence, the percent of children is about 27%.</u>
<u>Solution of Question B:</u>
<u>Percent of women: Total women/Total attendance</u>
- => 850/1500
- => 85/150
- => 17/30
- => 17/30 x 100
- => 17/3 x 10
- => 170/3
- => 56.67%
<u>Hence, the percent of women is 56.67%.</u>
<u>Solution of Question C:</u>
- 400 + 850 + m = 1500
- => 1250 + m = 1500
- => m = 1500 - 1250
- => m = 250
<u>Percent of men: Total men/Total attendance</u>
- => 250/1500
- => 1/6
- => 0.17 (Rounded to nearest hundredth)
- => 0.17 x 100
- => 17%
<u>Hence, the percent of men is about 17%</u>
Hoped this helped.
Answer:
Step-by-step explanation:
3 pieces such that each piece is 2 cm longer then the next...
x , x + 2, x + 4
x + x + 2 + x + 4 = 30
3x + 6 = 30
3x = 30 - 6
3x = 24
x = 24/3
x = 8
x + 2 = 8 + 2 = 10
x + 4 = 8 + 4 = 12
check...
8 + 10 + 12 = 30
18 + 12 = 30
30 = 30 (correct)...it checks out
the ribbon lengths are : 8 cm, 10 cm, and 12 cm
Answer:
f(-2)=4(-2)+1= 7
Step-by-step explanation:
Answer:
The correct option is (b).
Step-by-step explanation:
If X N (µ, σ²), then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).