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rewona [7]
2 years ago
13

Please help with 11,12,13

Mathematics
1 answer:
faltersainse [42]2 years ago
3 0

Problem 11

<h3>Answer:  h = 2A/b</h3>

------------------

Explanation:

We need to get h by itself. To do so, we first multiply both sides by 2. Then we divide both sides by b

A = (1/2)*b*h

2A = b*h

b*h = 2A

h = 2A/b

================================================

Problem 12

<h3>Answers:</h3>
  • Equation:   (n+2)/5 = 14
  • Solution to that equation:  n = 68

------------------

Explanation:

The number n is increased by 2 to get n+2

Then we divide by 5 to get (n+2)/5

This is set equal to 14 to get the equation (n+2)/5 = 14

Solving the equation would look like this

(n+2)/5 = 14

n+2 = 5*14 .... multiply both sides by 5

n+2 = 70

n = 70-2 .... subtract 2 from both sides

n = 68

================================================

Problem 13

<h3>Answer: Not a solution</h3>

------------------

Explanation:

We'll replace every copy of x with -3 and simplify

-2x + 5 > 13

-2*(-3) + 5 > 13

6 + 5 > 13

11 > 13

The last inequality is false because 11 is not greater than 13. Since the last inequality is false, this makes the first inequality false when x = -3.

Therefore, x = -3 is not a solution.

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x + 3

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2 years ago
Your parents gave you a gift card for your favorite coffee shop. The card was worth $50 when you got it. Each day, you buy a dri
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50=3x+b. you never specify the variable that replaces b

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3 years ago
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it cl
valentina_108 [34]

Answer:

Step-by-step explanation:

An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.

a) Let X represent the price of the option

<h3><u>  x                  P(X=x) </u></h3>

$1000         20/100 = 0.2

$200          50/100 = 0.5

$0              30/100 = 0.3

b) Expected option price

= \sum x.P(X=x)\\\\ = 1000 * 0.2 + 200 * 0.5 + 0 = \$ 300

Therefore expected gain = $300 - $150 = $150

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B2%7D%5E%7Bx%20%2B%202%7D%20-%20%20%7B2%7D%5E%7B%20x%20%2B%203%7D%20%7D%7B%2
weeeeeb [17]

I suppose you just have to simplify this expression.

(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)

Divide through every term by the lowest power of 2, which would be <em>x</em> + 1 :

… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)

Recall that <em>n</em>ª / <em>n</em>ᵇ = <em>n</em>ª⁻ᵇ, so that we have

… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)

… = (2¹ - 2²) / (2⁰ - 2¹)

… = (2 - 4) / (1 - 2)

… = (-2) / (-1)

… = 2

Another way to get the same result: rewrite every term as a multiple of <em>y</em> = 2ˣ :

… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)

… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)

… = (4<em>y</em> - 8<em>y</em>) / (2<em>y</em> - 4<em>y</em>)

… = (-4<em>y</em>) / (-2<em>y</em>)

… = 2

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3 years ago
Help!!! EASY!!! HELP DUE SOON!!!
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