Answer:
I'll list the answers as coordinates (just input the second number in each coordinate)
(-2, 11)
(0, 1)
(2, -9)
(4, -19)
Step-by-step explanation:
So you see how the x column is filled out? You plug in the numbers in each area and solve for y.
So we start off with -2. You take the x out and place -2 instead. Your equation should look like this:
y = -5 (-2) + 1
Next you multiply -5 and -2, giving you 10. Your equation would look like this now:
y = 10 + 1
Next you add 10 and 1 together, and you have your answer. Keep doing the same thing, but instead of -2 for x, use 0, 2, and 4.
Hope I helped! Have a nice day or night! ^-^
0.25 or 1/4 as a fraction
Answer:
<u>The correct answer is A. x = 6 + 3 √10</u>
Step-by-step explanation:
Let's solve for x:
x² - 12x + 36 = 90
Factoring this quadratic equation, we have:
(x - 6) (x - 6) = 90
(x - 6)² = 90
x - 6 = √90 (Square root to both sides of the equation)
x = 6 + √90 (Adding 6 to both sides of the equation)
x = 6 + √9 * 10
x = 6 + √3² * 10
x = 6 + 3 √10
<u>The correct answer is A. x = 6 + 3 √10</u>
Answer:
z = 55.15432893
x = 59.61543424
y = 22.5166605
Step-by-step explanation:
To find length "z" you will have to use SOHCAHTOA.
Labelling the triangle will show us that the side marked "z" is the hyp and the side marked 39 is the opp.
sin 45 = 
z sin 45 = 39
z = 
z = 55.15432893
Using Pythagoras' theorem, you can find that the adj = 39
In the other triangles POV, the adj is actually the opp.
Therefore, use tangent to find y.
tan 60 = 
y tan 60 = 39
y = 
y = 22.5166605
Use Pythagoras's Theorem to find x.

If the two diagonals are
and
, the are of the rhombus is

So, in your case, the area is

The other options are wrong because:
- option A doens't divide by 2, thus getting twice the area of the rhombus
- option B summed the diagonals instead of multiplying them
- option D took the difference of the diagonals.