A researcher wishes to examine the effects of a new reading program on

Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac

TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

6 0

1 year ago

Does anyone know matrices?

Sunny_sXe [5.5K]

Answer:

this is Geometry right?

Step-by-step explanation:

3 0

3 years ago

SOMEONE PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!!!!!

yulyashka [42]

2(5x^2+2x)+2(3x^2)
10x^2+4x+6x^2
16x^2+4x

D is the correct answer.

5 0

3 years ago

Read 2 more answers

Solve this thing pls <img src="https://tex.z-dn.net/?f=3%5Cleft%28q-7%5Cright%29%3D27" id="TexFormula1" title="3\left(q-7\ri

evablogger [386]

Answer:

Solution of equation ( q ) = 16

Step-by-step explanation:

In this question we have given an equation that is 3 ( q - 7 ) = 27 and we have asked to solve this equation that means to find the value of  q .

Solution : -

$\quad \: \longmapsto \: 3(q - 7) = 27$

Step 1 : Solving parenthesis :

$\quad \: \longmapsto \:3q - 21 = 27$

Step 2 : Adding 21 on both sides :

$\quad \: \longmapsto \:3q - \cancel{ 21} + \cancel{21} = 27 + 21$

On further calculations we get :

$\quad \: \longmapsto \:3q = 48$

Step 3 : Dividing by 3 from both sides :

$\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}} = \cancel {\frac{48}{3} }$

On further calculations we get :

$\quad \: \longmapsto \: \pink{\boxed{\frak{q = 16}}}$

Therefore, solution of equation ( q ) is 16 .

Verifying : -

Now we are very our answer by substituting value of q in the given equation . So ,

3 ( q - 7 ) = 27

3 ( 16 - 7 ) = 27

3 ( 9 ) = 27

27 = 27

L.H.S = R.H.S

Hence, Verified.

Therefore, our solution is correct .

<h2>#Keep Learning</h2>

3 0

2 years ago

Read 2 more answers

3. Which polynomial is equal to

Nataly_w [17]

Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?

<h3>Answer:</h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is $x^3 + 2x^2 + x + 3$

<h3>Solution:</h3>

Given that two polynomials are: $(-3x^2 + 2x - 3)$ and $(x^3 - x^2 + 3x)$

We have to find the result when $(-3x^2 + 2x - 3)$ is subtracted from $(x^3 - x^2 + 3x)$

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When $(-3x^2 + 2x - 3)$ is subtracted from $(x^3 - x^2 + 3x)$ , the result is:

$\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)$

Let us solve the above expression

There are two simple rules to remember:

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

$\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3$

Removing the brackets we get,

$\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3$

Combining the like terms,

$\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3$

$\rightarrow x^3 + 2x^2 + x + 3$

Thus the resulting polynomial is found

5 0

3 years ago