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Yakvenalex [24]
2 years ago
11

Find the distance between (5, 3) and (1, 3).

Mathematics
1 answer:
Dafna11 [192]2 years ago
7 0

Answer: 4 units

Step-by-step explanation:

(5-1,3-3)=(4,0)==> 4 units

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The answer is 68!!!!!!!!!
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Mrs. JOHNSON paid $40.68 for 3kg of shrimp. What’s the cost of 1 kilogram of shrimp?
Goshia [24]

Answer:

It is 13.56

Step-by-step explanation:

You would have to divide 40.68 by 3. 3 goes 1 time into 4 so it is 10.

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Darlene has 59 pages to type. so far she gas type 23 pages. what fraction of the job is finished ​
coldgirl [10]

Answer:

\frac{23}{59}

Step-by-step explanation:

A fraction can be found be taking the current amount over the total amount:

\frac{current}{total}=\frac{23}{59}

Since Darlene has only typed 23 pages out of 59, her fraction is 23 over 59.  Fractions must always be in simplest form, which means that both the numerator and denominator can no longer be divided by the same factor.  Since the numbers 23 and 59 are both prime and have no other factors other than 1 and themselves, the fraction 23/59 is in simplest form.

4 0
3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

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