It would be 6
6•4 is 24
24 minus 4 is 20
3(x+5)+2x
First, distribute 3 to all terms within the parenthesis
3(x) = 3x
3(5) = 15
3x + 15 + 2x
Combine like terms
(3x + 2x) + 15
5x + 15
(B) is your answer
hope this helps
Answer:
If you use the formula it should help for your answer.
Step-by-step explanation:
The value of
is ![396](https://tex.z-dn.net/?f=396)
Explanation:
It is given that
and ![y=y(t)](https://tex.z-dn.net/?f=y%3Dy%28t%29)
Also, given that
and
when ![x=22](https://tex.z-dn.net/?f=x%3D22)
Now, we need to determine the value of
when ![x=2](https://tex.z-dn.net/?f=x%3D2)
To determine the value of
when
, we need to differentiate the function
with respect to
Thus, we have,
![\frac{dy}{dt}=3x^2(\frac{dx}{dt} )+0](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D3x%5E2%28%5Cfrac%7Bdx%7D%7Bdt%7D%20%29%2B0)
Simplifying, we get,
![\frac{dy}{dt}=3x^2(\frac{dx}{dt} )](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D3x%5E2%28%5Cfrac%7Bdx%7D%7Bdt%7D%20%29)
Substituting
and
, we get,
![\frac{dy}{dt}=3(2)^2(33 )](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D3%282%29%5E2%2833%20%29)
Squaring the term, we have,
![\frac{dy}{dt}=3(4)(33 )](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D3%284%29%2833%20%29)
Multiplying the terms, we get,
![\frac{dy}{dt}=396](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D396)
Thus, the value of
is ![396](https://tex.z-dn.net/?f=396)
Answer:
B. 5
Step-by-step explanation:
-15 / -3
Both are negative so they cancel each other out.
15 / 3 equals 5