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Simora [160]
3 years ago
8

Simplify 1 to lowest terms and find an equivalent fraction that has a denominator of 32.

Mathematics
1 answer:
love history [14]3 years ago
6 0

Answer:

Option C

Step-by-step explanation: 3/4 x 8 will get 24 as the numerator and 32 as the denominator

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16 2/3 or 16.66 repeating

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Equation A (y=mx + b) is in slope intercept form.
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A salesman will earn a commission of 1/10 of the total amount sold.if he sells a car with a price of 24,000 what is his commissi
nydimaria [60]

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Step-by-step explanation:

1/10=0.1

if the total sales is  26,000

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Plz help fifty points
likoan [24]

Answer:

for question 13

  1. 130
  2. 50
  3. 50
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  5. 130
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  7. 50
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Step-by-step explanation:

for 14

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3 years ago
Read 2 more answers
The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

7 0
3 years ago
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