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lora16 [44]
3 years ago
12

I leave my family's vacation cabin at 8 a.m. and start driving home at a nice, safe 45 mph. Two hours later, my husband, who alw

ays drives as fast as the law will allow, leaves the cabin and starts driving home 65 mph. When can I expect him to pass me?​
Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

2:30 pm

Step-by-step explanation:

In two hours (from 10am), she is 45 * 2 = 90 miles from vacation cabin.

From then on her average is still 45 mph and her husband's is 65 mph. So, husband catches her 20 miles (65-45=20) in every hour.

<em>The husband has to catch up 90 miles. How long would it take if he is catching up at 20 miles an hour?</em>

<em>90/20 = 4.5 hours</em>

<em />

<em>So husband starts at 10am and 4.5 hours form that time is 2.30pm</em>

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Answer:

x=  0.5

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Step-by-step explanation:

Let's solve your equation step-by-step.

4x2+4x−3=0

Step 1: Factor left side of equation.

(2x−1)(2x+3)=0

Step 2: Set factors equal to 0.

2x−1=0 or 2x+3=0

x= 1/2 or x= −3/2

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2 years ago
Sistema de ecuaciones.5x+2y=-152x-2y=-6
Zolol [24]

Tnemos el sisema de ecuaciones:

\begin{gathered} 5x+2y=-15 \\ 2x-2y=-6 \end{gathered}

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\begin{gathered} (5x+2y)+(2x-2y)=(-15)+(-6) \\ 7x+0y=-21 \\ x=-\frac{21}{7} \\ x=-3 \end{gathered}

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

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7 0
11 months ago
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8 0
2 years ago
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d1i1m1o1n [39]
2 less than (3 times a number) is the same as (the number plus 10)
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divide eq2 by 2:

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8 0
3 years ago
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