Answer:
There is a 99% probability that at least one of the intervals will cover the true mean yields at their location
Step-by-step explanation:
In a 90% confidence interval of the mean of a population, there is a 90% probability that it cover the true mean of the population.
What is the probability that at least one of the intervals will cover the true mean yields at their location?
This is 1 subtracted by the probability that none of them cover the true mean yields at their location.
For each one, there is a 10% probability that it does not cover the mean. So the probability that both do not cover the mean is
The probability that at least one of the intervals will cover the true mean yields at their location is 1-0.01 = 0.99 = 99%.
It would be 9/8, 6/5, 1 1/4, 14/1
First we substitute, what that means in here is that 2(c +3)
Or minus I can't see the sign but what we do is we substitute 2 with c so that becomes 2c and 2 with 3 and that becomes 6 which gives us 2c + 6 = c-13
Now we can either add 13 on both sides or subtract 6 on both sides, we can do this because they are like terms even if they are negative because they don't have any variable behind it. We will add 13 because we do the opposite of the sign you are solving some get 2c + 19 = c now we subtract 2c on both sides and we get 19 = -1c and at the end we divide -1 on both side and we get -19 = c or
c = -19.
Answer: I and III
Step-by-step explanation:
We observe in the case provided that the researcher, who has no interest in the population to intervene, is going to carry out surveys to assess whether the neighborhood is a good place to live, obtaining the following conclusions:
i. The Minneapolis Resident Survey was an observational study.
ii. The Minneapolis Resident Survey was an experiment.
iii. The figure 50.1% is a descriptive statistic for the sample.
iv. The figure 50.1% is a statistical inference for the population.:By estimating the sample, obtained by a lower percentage of the total of the respondents, it is known that with a 95% confidence interval that the rating obtained from the respondents considering that the neighborhood is a good place to live was found between 0.44 and 0.50, taking this interval as a statistical inference for the population.
The correct answer is I and III, since in this study no interventions were made to the population and only one observation of a characteristic of the neighborhood was made and in III we know that the descriptive statistic only describes data and summarizes it, which is a of the ways to display the data from the descriptive survey.
C=50h+25
C=50(8)+25
C=400+25
C=$425
C=50(10)+25
C=500+25
C=$525