Write the formula for a triangle with a height of 2 1/2 and a 13 in base
1 answer:
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Answer:
0.9987 = 99.87% probability that the mean weight of 4 eggs in a package is less than 68.5g
Step-by-step explanation:
To solve this question, we use the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean weight of 67g and a sample standard deviation of 1g.
This means that
Sample of 4
This means that
What is the probability that the mean weight of 4 eggs in a package is less than 68.5g?
This is the pvalue of Z when X = 68.5. So
By the Central Limit Theorem
has a pvalue of 0.9987
0.9987 = 99.87% probability that the mean weight of 4 eggs in a package is less than 68.5g
Answer:
Peculiar purples would be more abundant
Step-by-step explanation:
Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd
The function representing would be
i) for I bacteria where t is no of minutes from start.
ii) for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.
a) Here P0 =3, time t = 60 minutes.
i) I bacteria P =
ii) II bacteria P =
b) Since II is multiplying more we find that I type will be more abundant.
The difference in two hours would be
c) i) for I bacteria where t is no of minutes from start.
ii) for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.
d) At time 36 minutes we have t = 36
Peculiar purples would be
The rate may not be constant for a longer time. Hence this may not be accurate.
e) when splits into 2, we get
where P0 is initial and t = interval of time