Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
10.44yd
a^2 + b^2 = c^2
3^2 + 10^2 = c^2
109 = c^2
C (Hypotenuse) ≈ 10.44
Do you have an image attached so I can help you?
Answer:
of a day
Step-by-step explanation:
To get minutes to days you divide the minutes by the amount of minutes in a day which is 1440

Answer:
9
Step-by-step explanation: