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Taya2010 [7]
3 years ago
13

Hello I need help with question B and C

Mathematics
1 answer:
Tanzania [10]3 years ago
6 0

Answer: a) 22.94 psi

               b) 5.93 X 10 --5

Step-by-step explanation:

a)The pressure at which will trigger a warning is

31 - 31*0.26 = 22.94 psi

b) The probability that that the TPMS will trigger warning at 22.94 psi, given that tire pressure has a normal distribution with average of 31 psi and standard deviation of 2 psi

where x = 22.94,

do not nothe rest

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Write the equation of each line in slope intercept form (If possible please show work)
Igoryamba

Answer:

y= -2/3 x - 9

Step-by-step explanation:

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = -2/3 x+b

We have a point to substitute into the equation

-5 = -2/3(-6) +b

-5 = 4 +b

Subtract 4 from each side

-5-4 = 4-4+b

-9 = b

y= -2/3 x - 9

8 0
3 years ago
What is the percent increase from 48 to 50?
Novosadov [1.4K]

Answer:

4%

Step-by-step explanation:

Since percentages are counted with % (100), we multiply 50 by 2 to get 100. We also 48 by 2 to get 96. Then we subtract 96 from 100 to get 4%.

48 increases by 4% o get 50.

4 0
3 years ago
Read 2 more answers
How did you get that ? 709 × 68= 48212?
algol13
You can get the answer by doing proper multiplication. In another words, it mean like this:
709
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5672
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48212. To do this right, you need to rearrange this into the right position to get the correct answer. Also, you can use calculator to find the answer more quicker. Hope it help!
7 0
3 years ago
Find c.
Alexxx [7]

9514 1404 393

Answer:

  14.9 cm

Step-by-step explanation:

To find c using the Law of Sines, you must know angle C. That is found from ...

  C = 180° -A -B = 180° -150° -12° = 18°

Then the law of sines tells you ...

  c/sin(C) = b/sin(B)

  c = b·sin(C)/sin(B) = (10 cm)·sin(18°)/sin(12°)

  c ≈ 14.9 cm

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3 years ago
6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t
Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}

Therefore, there 12 possible combinations from these

3 0
2 years ago
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