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bekas [8.4K]
3 years ago
9

Find the area of the shape shown below.

Mathematics
2 answers:
krek1111 [17]3 years ago
6 0

Answer:

12.5

Step-by-step explanation:

frozen [14]3 years ago
5 0

Answer:

you multiply the numbers lol

Step-by-step explanation:

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A ladder that is 6 meters long leans
alexira [117]

Answer:

Height of building from base to ladder = 5.8 meter (Approx.)

Step-by-step explanation:

Given:

Length of ladder = 6 meters

Distance of ladder from base = 1.5 meters

Find:

Height of building from base to ladder

Computation:

Perpendicular = √Hypotenuse² - Base²

Height of building from base to ladder = √Length of ladder² - Distance of ladder from base²

Height of building from base to ladder = √6² - 1.5²

Height of building from base to ladder = √36 - 2.25

Height of building from base to ladder = √33.75

Height of building from base to ladder = 5.8 meter (Approx.)

6 0
3 years ago
How many times do 4896 go into 48?
EleoNora [17]
If you are asking how many times 48 goes into 4896 it is 102

4896÷48= 102

hopefully it helps ;)
4 0
3 years ago
Can y’all help me with these plz
nalin [4]

Answer:

1)  160 (less than or equal to) 42+65+x      OR      53

2)  2000 (greater than or equal to) 637+x    OR    $1363

3)  1st piece: 5ft

    2nd piece: 10ft

    3rd piece: 6ft

Step-by-step explanation:

1) You must reach at least 160 blankets. Some have already been added, so just add the total to "x"

2) Your brother already spent $637 of 2000 dollars.

3 0
4 years ago
GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out
Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

Area=length\times width

Area of garden and the walkway together is

Area=(14+2x)\times (10+2x)

396=140+28x+20x+4x^2

396=140+48x+4x^2

396=4(35+12x+x^2)

Divide both sides by 4.

99=35+12x+x^2

0=35-99+12x+x^2

0=-64+12x+x^2

Splitting the middle term, we get

x^2+16x-4x-64=0

x(x+16)-4(x+16)=0

(x+16)(x-4)=0

Using zero product property, we get

(x+16)=0\text{ and }(x-4)=0

x=-16\text{ and }x=4

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0
3 years ago
Read 2 more answers
If LN XZ, is ALMNAXYZ?<br> Y<br> M<br> Х<br> N<br> Z<br> Yes<br> No
Nikolay [14]

Answer:

Yes

Step-by-step explanation:

Yes

because we are given that

LN ≅ XZ ( side)

the picture shows that

LM ≅XY ( side)

and

MN ≅ YZ (side)

By the <u>SSS theorem of congruency</u> we conclude that ΔLMN ≅ ΔXYZ

5 0
3 years ago
Read 2 more answers
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