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Hunter-Best [27]
3 years ago
15

It has been observed that the average number of traffic accidents requiring medical assistance on the Hollywood Freeway between

7 and 8 a.m. on Wednesdays is 1. An ambulance can only service one accident requiring medical assistance at a time. The hospital dispatcher needs to know the chance there will be a need for exactly 2 ambulances on the Hollywood Freeway between 7 and 8 a.m. on Wednesdays. What will you, the statistics consultant hired by the hospital, tell the dispatcher
Mathematics
1 answer:
Vesna [10]3 years ago
7 0

Answer:

0.184

Step-by-step explanation:

As the statistician consultant, I would have to calculate the chance of having 2 ambulances on the freeway at this hours and relay the message to the dispatcher.

Probability of having the need for 2 ambulances.

We will have a poisson distribution:

Lambda = 1

P(x=2) = e^-2*1/2!

= 2.71828^-1/2

= 0.368/2

= 0.184

I would tell the dispatch rider that the possibility that 2 ambulances would be required is 0.184.

Thank you

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Step-by-step explanation:

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3 years ago
A rectangular bed of a truck is 1 9/10 meters long,1 1/2 meters wide, and 1/2 meter tall. What is the volume of the truck bed?
Sophie [7]

Answer:

The volume of the truck bed is 1\frac{17}{40}\ m^{3}

Step-by-step explanation:

we know that

The volume is equal to

V=LWH

substitute the values , but first convert to an improper fractions

L=1\frac{9}{10}\ m=\frac{10*1+9}{10}=\frac{19}{10}\ m

W=1\frac{1}{2}\ m=\frac{1*2+1}{2}=\frac{3}{2}\ m

H=\frac{1}{2}\ m

Find the volume

V=(\frac{19}{10})(\frac{3}{2})(\frac{1}{2})=\frac{57}{40}\ m^{3}

Convert to mixed number

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