Plz help with my math at least the first 4 questions

Mathematics

1 answer:

Alchen [17]2 years ago

3 0

Answer:

1. 18ft , 12ft, 30ft (ill try to answer the rest, but i have to turn in an assignment, sorry!! <3 hope i helped a little for now)

Step-by-step explanation:

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Can y'all help me with this? > sorry for the bad picture quality.

MatroZZZ [7]

I think It is be but idk as I am in year 7

8 0

3 years ago

Read 2 more answers

Find the x intercepts of f(x) = –16x^2 + 22x + 3

Helga [31]

That is where the line crosses the x axis or where y=0

0=-16x^2+22x+3
we gon do grouping
ac method
-16 times 3=-48

what 2 numbers multiply to get -48 and add to get 22
-2 and 24
0=-16x^2-2x+24x+3
group
0=(-16x^2-2x)+(24x+3)
undistribute
0=-2x(8x+1)+3(8x+1)
undistribute
0=(8x+1)(-2x+3)
set eaqual to 0

8x+1=0
8x=-1
x=-1/8

-2x+3=0
3=2x
3/2=x

x intercepts ate x=-1/8 and x=3/2

4 0

3 years ago

The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.

nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.

With reference to table we get

$\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418$

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85$

and

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97$