<h3>
Answer: -6 and 0</h3>
Explanation:
The solutions, or roots, are the x intercepts of the graph. This is where the curve crosses or touches the x axis. In this case, the two x intercepts are -6 and 0.
Rise over run, so if the line had a slope of 3/5 you would go up 3 and over 5 to plot your next point. I hope this helped <3
Answer:
Therefore required expression is
y =462 - t×15
where y represents the amount of money in her bank account in dollar after t week.
Step-by-step explanation:
Given that,
Holly has $462 in her bank account and takes out $15 each week but does not put any back in.
She takes out $15 on first week.
The remaining amount of her bank account is =$(462-15)
=$(462 - 1×15)
If she withdraws $15 on second week.
The remaining amount of her bank account is =$(462-15-15)
=$(462 - 2×15)
Similarly after third the amount in her account is =$(462 - 3×15)
From the above it is cleared that
The amount in her account after t week is
=$(462 - t×15)
Therefore required expression is
y =462 - t×15
where y represents the amount of money in her bank account in dollar after t week.
Answer:
The answer to your question is 6.- B 7.- D
Step-by-step explanation:
Data
Parallelogram ACFG
6.-
m∠GAC = 112°
m∠ACF = ?
Process
These angles are supplementary, they measure the same.
∠GAC + ∠ACF = 180
-Substitution
112 + ∠ACF = 180°
-Solve for ∠ACF
∠ACF = 180° - 112°
-Result
∠ACF = 68°
7.-
m∠AGF = 2a + 10
m∠ACF = a + 20
The angles ∠GAC and ACF are equal, they measure the same.
∠GAC = ∠ACF
-Substitution
a + 20 = 2a + 10
-Solve for a
a - 2a = 10 - 20
-Result
-a = -10
a = 10
-Find ∠AGF
∠AGF = 2(10) + 10
20 + 10
= 30°
Answer:
Slope= -7
Step-by-step explanation:
I like to use the rise/run method.
Take the point at (1,-2) and count up to (1, 7). Then because it is going left, you count your run over 3 points. Or you could do.
