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vazorg [7]
3 years ago
5

(THIS IS 6TH GRADE MATH) PLEASE HELP​

Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

Step-by-step explanation:

10r - r-6r+11 - Constant = 11 & coefficient = r

19-5n-8+14 - constant = 8,14,19 & coeff = n

-5-13y-2y-18 - constant = -5,18 & coeff = y

8a-7b+1-2b+3a - constant = 1 & coeff = a,b

11x-4y+2x+8 - constant = 8 & coeff = x,y

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Find the area and perimeter of ABC at right. Give approximate (decimal) answers, not exact answers
AURORKA [14]

Answer:

Area of Δ ABC = 21.86 units square

Perimeter of Δ ABC = 24.59 units

Step-by-step explanation:

Given:

In Δ ABC

∠A=45°

∠C=30°

Height of triangle = 4 units.

To find area and perimeter of triangle we need to find the sides of the triangle.

Naming the end point of altitude as 'O'

Given BO\perp AC

For Δ ABO

Since its a right triangle with one angle 45°, it means it is a special 45-45-90 triangle.

The sides of 45-45-90 triangle is given as:

We are given BO (Leg 1) x=4

∴ AO (Leg2) =x=4

∴ AB (hypotenuse) =x\sqrt2=4\sqrt2=5.66  

For Δ CBO

Since its a right triangle with one angle 30°, it means it is a special 30-60-90 triangle.

The sides of 30-60-90 triangle is given as:

We are given BO (side opposite 30° angle) =x=4

CO (side opposite 60° angle) =x\sqrt3=4\sqrt3=6.93

BC (Hypotenuse) =2x=2\times 4 =8

Length of side AC is given as sum of AO and CO

AC=AO+CO=4+6.93=10.93

Perimeter of Δ ABC= Sum of sides of triangle

⇒ AB+BC+AC

⇒ 5.66+8+10.93

⇒ 24.59 units

Area of Δ ABC = \frac{1}{2}\times base\times height

⇒  \frac{1}{2}\times 10.93\times 4

⇒ 21.86 units square

6 0
3 years ago
Nolan invested $5,300 in an account paying an interest rate of 3.8% compounded annually. Assuming no deposits or withdrawals are
Sveta_85 [38]

It will take Nolan 7 years compounded annually at the rate of 3% for his money to reach $6880

To solve this problem, we would use the formula of compound interest.

Data given;

  • A = 6880
  • P = 5300
  • r = 3.8 % = 0.038
  • N = 1

<h3>Compound Interest</h3>

The formula used in calculating compound interest is given as

A = P(1 + r/n)^n^t

let us plug in the values and solve for t.

6880 = 5300(1 + \frac{0.038}{1})^1^*^t\\&#10; \frac{6880}{5300}=(1+0.038)^t\\&#10; 1.29=(1.038)^t

Take the natural log of both sides

ln(1.29)=ln(1.038)^t\\&#10;0.25=t*0.037\\&#10;t=0.25/0.037\\&#10;t=6.75\\&#10;t=7

The time it will take for $5330 compounded annually at the rate of 3% is 7 years.

Learn more on compound interest here;

brainly.com/question/2455673

3 0
3 years ago
1
MatroZZZ [7]
Write every number which have the power
4 0
1 year ago
Which is the correct way to solve the given equation
Karolina [17]

Option 2. x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form ax^{2} +bx+c=0 the solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Here a is the coefficient of x^{2}, b is the coefficient of x and c is the constant term.

x^{2} -4x=21 can also be written as x^{2} -4x-21=0.

Comparing x^{2} -4x-21=0 with ax^{2} +bx+c=0, we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.

Step 2:

Substituting the values, we get

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}= \frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

\frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.

This is option 2.

7 0
4 years ago
Which number is equal to10^-3
8090 [49]

Answer:

-1000

Step-by-step explanation:

take -10 x -10 x -10= -1000:)

4 0
3 years ago
Read 2 more answers
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