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3 years ago

4x/3 + 2(3- x) = 5 Solve for x as an FRACTION

Mathematics

1 answer:

forsale [732]3 years ago

6 0

Answer:

<h2>The answer is .... x = 3/2 and if you want to write it as a mixed fraction i will be x= 1 and 1/2</h2>

Step-by-step explanation:

Hope this Helped :)

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Natalija [7]

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A rectangular flowerbed at a city park has an area of 126 square meters.the width of the flowerbed is 3 meters.what is the perim

Alona [7]

First we need to find the length. So we do 126/3 to get 42. The length is 42. Now to find perimeter we do 2(42)+2(3) or 42+42+3+3.

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3 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

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3 years ago