Answer:
W = 2747,1 [J]
Step-by-step explanation:
Chain is 64 meters long with mass 24 Kg
Then weight of the chain is p = 24 * 9.8
p = 235.2 [N] N = kg*m/s²
And by meter is 235,2 / 64 = 3.675
Total work has two component
- work to lift the 13 top meters of chain W₁
W₁ = ∫₀ᵇ F(y) dy
- work to lift last ( 64 - 13 ) meters 51 W₂
W₂ = 3.675 * 51 * 13 Kg m² /s² [J]
W₂ = 2436,53 [J]
We need to calculate W₁
W₁ = ∫¹³₀ mgy dy ⇒ W₁ = ∫¹³₀ 3,675 ydy
W₁ = 3,675* ∫¹³₀ ydy W₁ = 3,675* y²/2 |₀¹³
W₁ = 3,675* 84,5 [J]
W₁ = 310,54 [J]
And total work W
W = W₁ + W₂
W = 310,54 + 2436,53 [J]
W = 2747,1 [J]
Answer:
The answer to your question is: g(3) = 34
Step-by-step explanation:
Function g(x) = 4(x)² - 3(x) + 7
g(3) = 4(3)² - 3(3) + 7 substitution
g(3) = 4(9) - 3(3) + 7 simplify
g(3) = 36 - 9 + 7
g(3) = 36 - 2
g(3) = 34
25
The triangle given by 9, unknown, and 15 and the triangle given by 15, unknown, and x are similar triangles and therefore 9:15 = 15:x
X is 25 in this case
The roots are 3 and 17 so the distributed equation is
(x-3)(x-17)
distribute
x²-3x-17x+51
x²-20x+51
I hope I've helped!
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, 
,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
