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VikaD [51]
3 years ago
10

Find the HCF of 32 and 50 using prime factors

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0

Answer:

It’s 32

Step-by-step explanation:

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Write the slope-intercept form of the equation of the line that has the same y-intercept as the black line shown and passes thro
Mazyrski [523]

Answer:

y = 0.5x + 2

Step-by-step explanation:

the y-intercept is 2, as shown in the graph

the slope is 0.5. this is because while the x-value goes up by 2, the y-value goes up by one (from 0, 2 to 2, 3).

using the slope formula of rise / run, you get 1/2, which is equal to 0.5

5 0
3 years ago
Ry
yanalaym [24]

Answer:

3x + 2 = y

hope it was helpful

4 0
3 years ago
Please please please please help i need to pass please
labwork [276]

Answer:

D

Step-by-step explanation:

Solution:-

The standard sinusoidal waveform defined over the domain [ 0 , 2π ] is given as:

                                   f ( x ) = sin ( w*x ± k ) ± b

Where,

                 w: The frequency of the cycle

                 k: The phase difference

                 b: The vertical shift of center line from origin

We are given that the function completes 2 cycles over the domain of [ 0 , 2π ]. The number of cycles of a sinusoidal wave is given by the frequency parameter ( w ).

We will plug in w = 2. No information is given regarding the phase difference ( k ) and the position of waveform from the origin. So we can set these parameters to zero. k = b = 0.

The resulting sinusoidal waveform can be expressed as:

                           f ( x ) = sin ( 2x )  ... Answer

4 0
3 years ago
help !!!!! urgent !!! the figure in the graph below will be rotated 180 degrees clockwise about the origin and then translated 9
Roman55 [17]

Answer:

I think its the last one if you get it wrong im SOOO sorry

4 0
3 years ago
Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
3 years ago
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