Question

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Answer 1

Answer:

Trapezoid area:

• A = 1/2(a + b)h, where a, b - bases , h - height

17. a)

• a = RS = 4 units
• b = AT = 8 units
• h = 8 units, the distance between RS and AT

A = 1/2(4 + 8)*8 = 48 units²

17. b)

• a = SK = 4 units
• b = OC = 10 units
• h = SO = 6 units

A = 1/2(4 + 10)*6 = 42 units²

18. a)

• a = ME = 6 units
• b = AZ = 10 units
• h = MA = 8 units

A = 1/2(6 + 10)*8 = 64 units²

Answer 2

Area of trapezoid:

Line RS: 2x2 = 4 units (first base)

Line TA: 4x2 = 8 units (second base)

The height (aka that x-axis inside shape): 4x2 = 8 units (h)

Area formula: (4 + 8)8 ÷ 2

= (4 + 8)8 ÷ 2

= 12(8) ÷ 2

= 96 ÷ 2

ANSWER = 48 sq. units

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Area of trapezoid:

Line SK: 2x2 = 4 units (first base)

Line OC: 5x2 = 10 units (second base)

Line SO (height): 3x2 = 6 units (h)

Area formula: (b1 + b2)h ÷ 2

= (4 + 10)6 ÷ 2

= 14(6) ÷ 2

= 84 ÷ 2

ANSWER = 42 sq. units

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Area of trapezoid:

Line ME: 6 units (first base)

Line AZ: 10 units (second base)

Line MA (height): 8 units (h)

Area formula: (b1 + b2)h ÷ 2

= (6 + 10)8 ÷ 2

= (16)8 ÷ 2

= 128 ÷ 2

= 64

ANSWER = 64 sq. units