Answer:
157.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let us begin with the AA Similarity definition. It states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.
This means that we need:
- An angle of one triangle that is congruent to an angle of the other triangle.
- Another angle of one triangle that is congruent to another angle of the other triangle.
For this problem, it is unclear that there are more than one angles that are congruent to each other. We see that angle <DEF and <ABC are congruent, but the problem does not give any other angles. In another case, we must find one more to prove similarity by the AA similarity theorem.
Answer:
Class width = 9
Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.
Step-by-step explanation:
We are given;
Highest value = 82
Lowest value = 20
Frequency = 7
Formula for class width is;
Class width = (Highest Value - Lowest Value)/number of classes
Class width = (82 - 20)/7
Class width = 8.8 ≈ 9
Now,since class width is 9, limits between 20 and 82 would be done at intervals of 9.
Thus;
Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.
Answer:
The closest answer is $30.00, the original answer is $29.99
