Answer:
in the step-by-step
Step-by-step explanation:
okay one thing is that you labelled wrong since you have to label D', D", D'" (you just labelled with one for all of them)
a you reflected across the y-axis wrong
-it would be that D' (-2,6), E' (-2,3), F' (-5,3)
b you rotated correctly
this gets more confusing since you labelled the triangles wrong, but I hope this first part helps
9514 1404 393
Answer:
21 coins of ₹2
Step-by-step explanation:
Let x represent the number of ₹2 coins, and y the number of ₹5 coins. Then the total value of the coins is ...
2x +5y = 77
and the relationship between numbers of coins is ...
x = 3y
Substituting for x, we have ...
2(3y) +5y = 77
y = 77/11 = 7 . . . . simplify, divide by the coefficient of y
x = 3(7) = 21 . . . . find x from the second equation
Ram has 21 of the ₹2 coins.
So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.
First thing to do is to figure out how many additional lessons are in that, which are 5.
Then you can make a 1 variable equation with the information you have. I’m using x as my variable.
260= 3/2x + 5x
Combine like terms.
260 = 13/2x
Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)
X=40
Answer:
y = SQRT( x + 36 )
y = - SQRT( x + 36 )
Steps:
The 5 options you listed are unclear to me. But I provided the correct answer above.
55 adult tickets. Set up 2 equations: c+a=125 and 6.1c+9.4a=944. Isolate either variable from first equation and plug into second to find that 55 adult tickets were sold and 70 children’s tickets