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Mademuasel [1]
3 years ago
10

I ran 1½ miles in 20 minutes . How fast did I go?

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer:

4 MPH

Step-by-step explanation:

If you ran 1 1/2  miles in 20 minutes than in an hour you have ran 4 1/2 miles

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What is the reciprocal of -4
mario62 [17]

Answer: -4/1 = 1/-4

= 1/-4

Just flip the fraction:)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
4
VLD [36.1K]
Answer is D. 81

1/4 x 4 = 1

81^1 = 81
4 0
3 years ago
What are the vertex, axis of symmetry, maximum or minimum value, and range of y = 3x^2 + 6x − 1?
Bess [88]
The vertex is when x=-b/2a, which is also the line of symmetry. 
in this case, b=6, a=3, so x=-6/6=-1
when x=-1. y=3-6-1=-4

another way to do it is to write the equation into vertex form by making a square:
3x²+6x-1
3(x²+2x-1/3)
3(x²+2x+1-1-1/3))
3(x²+2x+1-4/3))
notice the bold part makes a square:
3(x+1)²-4

Either way, 
the vertex is (-1, -4)
the axis of symmetry is x=-1
the coefficient of x² is 3, a positive number, so this parabola opens upward. the function has a minimum value of y=-4
the range is all real number larger than -4
6 0
3 years ago
What is the vertex of the parabola defined by the equation(x − 2)^2 = -12(y − 2)?
zaharov [31]
X^2-4x+4=-12y+24
(x^2-4x-20)/-12=y
quadratic => vertex is (-b/2a,f (-b/2a))
Note it is a minimum since coefficient a is positive
6 0
4 years ago
Read 2 more answers
What is the length of BC in the right triangle below 21 and 72
sleet_krkn [62]
Im guessing 21 and 72 are the side lengths for the triangle?

Alright, so since it's a right triangle you can use the Pythagorean theorem or a^2+b^2=c^2

Since i cant see the picture, im going to use some general math <span>so i</span> can figure out if those two sides are the legs or if one of them is the hypotenuse
Alright 
so im guessing the side we're trying to find is the hypotenuse

21^2+72^2=c^2
441+5184=c^2
5625=c^2
<span>√5625=c</span>
75=c

The answer is 75, hope i helped!
3 0
3 years ago
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