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Viktor [21]
3 years ago
6

Whats the answer to m=18+12​

Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0

Answer:

m = 30

Step-by-step explanation:

Wewaii [24]3 years ago
3 0

Answer:

30

Step-by-step explanation:

10 + 10 = 20

8 + 2 = 10

20 + 10 = 30

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A 12-foot ladder is leaning against a wall. The distance from the base of the wall to the base of the ladder is 6 StartRoot 2 En
Hoochie [10]

Answer:

a

b

d

e

Step-by-step explanation:

he triangle is isosceles.

The leg-to-hypotenuse ratio is 1:StartRoot 2 EndRoot.

The leg-to-hypotenuse ratio is 1:StartFraction StartRoot 2 EndRoot Over 2 EndRoot. The nonright angles are congruent. The ladder represents the longest length in the triangle.

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3 years ago
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What is 80 in its simplest form as a fraction?
Ann [662]

I believe the correct given problem is:

“What is 80% in its simplest form as a fraction?”

 

Take note that you missed to place the percent sign which is very important.

 

Now to solve this, 80% when converted to decimal form is 0.80 which means that you have 80 parts per 100 parts. Therefore the fraction form of this would be 80 / 100.

fraction = 80 / 100

However this fraction is not yet the answer because we can still simplify this further. First step in simplifying is to divide both the numerator and denominator by 10 so that we are left with:

8 / 10

Next step is to divide by 2:

4 / 5

 

Now we can see that we can no longer divide this (numbers should be whole number). Therefore the simplest form as a fraction is 4/5

 

Answer:

4/5

6 0
3 years ago
Problem in the picture
STatiana [176]

Answer:

B)

Step-by-step explanation:

65 x 2.5 = 162.5

70 x 1.5 = 105

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3 years ago
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Match each set of vertices with the type of triangle they form.
Andrew [12]

Answer:  The calculations are done below.


Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.

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(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0
4 years ago
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Gwar [14]

Answer:

X=5

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3x=15 (add 8 to both sides)

X=5 (divide by 3)

4 0
3 years ago
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