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2 years ago

Don’t the permeter of the figure (HELPP PLEASEEE)

Mathematics

1 answer:

posledela2 years ago

8 0

Answer:

Step-by-step explanation:

the formular for calculating the perimeter of a semi circle is πr

from the figure, r= 12/2= 6

perimeter= 3.142×6 = 18.852

perimeter = 19 approximately

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The length of one leg of a right triangle is 24 feet and the length of the hypotenuse is 40 ft what is the length of the other l

Rama09 [41]

To solve for the other leg, you need to use Pythagorean theory.

The theory states that C^2 = A^2 + B^2

In your case, you have to solve for B.
C = 40 (hypotenuse) A = 24 (leg 1)

The formula rewritten for B is $b= \sqrt{c^{2}-a^{2} }$

Now, you can solve.

$b= \sqrt{c^{2}-a^{2} }

b= \sqrt{40^{2}-24^2 }

b = \sqrt{1600 - 576}

b = \sqrt{1024}

b = 32$

Therefore, B = 32.

So the second leg is 32 feet.

7 0

4 years ago

The points (12, 23) and (14, 45) lie on a line. What is the slope of the line?

ozzi

Answer:

slope= 11

Step-by-step explanation:

(12,23) = (x1,y1)

(14,45) = (x2,y2)

Now,

slope(m)= (y2-y1)/(x2-x1)

=(45-23)/(14-12)

=22/2

=11

5 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$