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ArbitrLikvidat [17]
2 years ago
15

Don’t the permeter of the figure (HELPP PLEASEEE)

Mathematics
1 answer:
posledela2 years ago
8 0

Answer:

19

Step-by-step explanation:

the formular for calculating the perimeter of a semi circle is πr

from the figure, r= 12/2= 6

perimeter= 3.142×6 = 18.852

perimeter = 19 approximately

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Dominic invested $520 in an account in the year 1995, and the value has been growing exponentially at a constant rate. The value
Tom [10]

Answer:

I believe the answer is $936.64

Step-by-step explanation:

I hope this helps!

6 0
3 years ago
I REALLY NEED THIS NOW. PLEASE HELP ME!!
Andre45 [30]

Answer:

4*-2... answer D. is correct :)

7 0
3 years ago
Read 2 more answers
A company is designing a new cylindrical water bottle. The volume of the bottle will be 205 cm to the square root of 3 cm. The h
Umnica [9.8K]

Answer:

19 cm

Step-by-step explanation:

Given :

Volume, V = 205 to the √3 = 205^√3

Height, h = 8.9

radius, r

Volume of cylinder:

V = πr²h

205 to the square root of 3 10094.275

company is designing a new cylindrical water bottle. The volume of the bottle will be 205 cm to the square root of 3 cm. The height of the water bottle is 8.9 cm. What is the radius of the water​ bottle?

10094.275 = π * r² * 8.9

10094.275 = 3.14 * 8.9 * r²

10094.275 = 27.946r²

r² = 10094.275 / 27.946

r² = 361.20643

r = √361.20643

r = 19 cm

8 0
3 years ago
How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit
Kisachek [45]
\sqrt{x-8} is undefined if the argument x-8 is negative, so you first need to require that

x-8\ge0\implies x\ge8

We're not done yet, though, because \dfrac1{\sqrt{x-8}} still doesn't exist when x=8, so we remove this from the domain and we're left with x>8, or in interval notation, (8,\infty)

To find the range, consider the limits of the function as you approach either endpoint of the domain.

\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty
\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0

Since \dfrac1{\sqrt{x-8}} is positive everywhere, the range is (0,\infty)
3 0
3 years ago
Simplify 10 - [14 = (3 + 4) · 2]+3
lora16 [44]

Answer:

There is a typo near the equal sign.

There can be two different answers if we think that = sign as + or -.

First way: Making = as +

=> 10 - [14 + (3+4) x 2] +3

=> 10 - [14 + 7 x 2] + 3

=> 10 - [14 + 14] + 3

=> 10 - 28 + 3

=> 10 + 3 - 28

=> 13 - 28

=> -15

=> So, -15 is the answer if we consider "=" sign as "+" sign.

Second way: Making = as -

=> 10 - [14 - (3+4) x 2] + 3

=> 10 - [14 - 7 x 2] + 3

=> 10 - [14 - 14] + 3

=> 10 - 0 + 3

=> 10 + 3

=> 13

=> So, 13 is the answer if we consider "=" sign as "-" sign.

5 0
3 years ago
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