Parallel lines, slope is the same so
1) 3x+8y = 12
8y = -3x + 12
y = -3/8(x) + 3/2, slope = -3/8
slope of a line that is parallel = -3/8
2)5x+4y = 5
4y = -5x + 5
y = -5/4(x) + 5/4; slope is -5/4
slope of a line that is parallel = -5/4
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perpendicular, slope is opposite and reciprocal
3)
3x+8y = 11
8y = -3x + 11
y = -3/8(x) + 11/8. slope = -3/8
slope of perpendicular line = 8/3
4)
x = -7, slope is undefined
so slope of perpendicular line is 0
5)
3x+2y = 12
2y = -3x + 12
y = -3/2(x) + 6 ; slope = -3/2
5x - 6y = 8
6y = 4x - 8
y = 2/3(x) - 4/3; slope is 2/3
slope is opposite and reciprocal, so the equals are perpendicular
6)
3x + y = 5
y = -3x + 5; slope = -3
6x + 2y = -15
2y = -6x - 15
y = -3x - 7.5; slope = -3
both have slope = -3 so equations are parallel
that would be 20 miles per hour. If in 8 hours you're going 160, then divide 160 by 8 and you'd get 20. Each hour is 20 miles. or 8 times 20 is 160. Your answer is 20 miles per hour
3.) 3, 4, 5
&
4.) 6, 8, 10
Those two are right triangles because when you add the squares of the first two it should give you the square root of the third number
a^2 + b^2 = c^2
So
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
Therefore they are right triangles
But 1 & 2 aren’t right triangles because when you add the squares of the first two number, it doesn’t equal to the square root of the third number.
Hope this helps!!
Answer:
hold my picolr
Step-by-step explanation:
Csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = [1/sin(x)] / [1/cos(x)]
cot(x) = 1/sin(x) * cos(x)/1
cot(x) = cos(x) / sin(x)
cot(x) = cot(x)
