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In-s [12.5K]
3 years ago
15

What i 8 divided by 231

Mathematics
1 answer:
Zepler [3.9K]3 years ago
3 0
8 divided by 231 is 0.034632035
231 divided by 8 is 28.875
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Find the 9th term of the geometric sequence 5, -25, 125, ...
arlik [135]

Answer:

Step-by-step explanation:

a = 5

r = -5

n = 9

t_9 = a r^(n - 1)

t_9 = (-1)^n*5 (-5) ^ 8

t_9 = (-1)^9 *  5 *  (-5) ^8

t_9 = -1 ( 1953125)

t_9 = - 1953125

6 0
3 years ago
This is the picture that goes with my question.​
german

Answer:

first u should make your equation: y= -1/5 (x-5) - 3

y= -1/5x +1 -3

y= -1/5 x -2

then u should setting some number like 1 ,2 ..... instead of *x* and when u done this u should dissolve it (now your *y* is came out too) so you have your x,y now

According to the points you get, you put it on the chart and connect it

if you do not understand something, tell me to draw on paper so you can understand better

7 0
3 years ago
Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the cho
Contact [7]

Answer:

9 packages of chocolate bars

Step-by-step explanation:

Let he bought c packages of chocolate bars and t packages of toffee bars,

Since, he bought 1 fewer package of chocolate bars than toffee bars.

⇒ c = t - 1  -----(1)

Also, he handed out out \frac{2}{3} of the chocolate bars and \frac{3}{5} of the toffee bars,

If he handed out the same number of each kind of candy bar.

\implies \frac{2}{3}\times c=\frac{3}{5}\times t

10c = 9t     ( By cross multiplication )

\implies t=\frac{10}{9}c    ( Division property of equality )

From equation (1),

c=\frac{10}{9}c-1

1=\frac{10}{9}c-c

1=\frac{10c-9c}{9}

1=\frac{c}{9}

\implies c = 9

Hence, he bought 9 packages of chocolate bars.

4 0
2 years ago
Find the GCF of the terms of the polynomial.
-BARSIC- [3]
<h3>Answer:   2z^3</h3>

====================================================

Explanation:

The GCF of the coefficients {6, -42, 14} is 2 as it is the largest factor found in each of the three values.

----------

For the variable portions, we can

  • write z^5 as z^3*z^2
  • write z^4 as z^3*z^1
  • write z^3 as z^3*1

Each time we see z^3 show up, so this is the largest common factor among the three variable terms.

----------

The two results we got were 2 and z^3

Putting the two results together, we end up with the overall GCF of 2z^3

4 0
3 years ago
F(x) = x 2+ 6 and g(x) = 2x - 1<br><br> g[f(x)] =
Tasya [4]

Answer:

Given,

f(x)=x^2+6

g(x)=2x-1

Now,

g[f(x)]=g(x^2+6) since f(x)=x^2+6

=2(x^2+6)-1 since x > x^2+6

=2x^2+12-1

=2x^2+11

6 0
3 years ago
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