uhhhhhhhh it's 2.......
Step-by-step explanation:
q(a) = ½a + 38
The slope of q is ½. So the perpendicular slope is -1/½ = -2.
Write h(x) in point-slope form:
h − (-7) = -2 (x − 12)
h + 7 = -2 (x − 12)
Simplify to get slope-intercept form.
h + 7 = -2x + 24
h = -2x + 17
Answer:
No
=2•2•2=8
=3•3=9
8≠9
m=-2
As the product of the roots of a quadratic equation is c/a in ax^2+bx+c=0
here a=2, b=+8, c=-m^3
Given c/a=4
-m^3/2=4
-m^3=8
m^3= -8
m=-2.
1. (6, -329°) (-6, 211°) (-6, -149°)
2. (5, -5π/3) (-5, 4π/3) (-5,-2π/3)
Notice: (+,+),(+,-),(-,+),(-,-).
If we consider angles beyond 360° or 2π, many other names for these points can be determined.
The polar coordinate can be written as (r, θ) = (r, θ + 2nπ) or (r, θ) = [ - r, θ + (2n + 1)π ], where n is any integer
-48xy
For part A:
Multiplying all the constants together:
For part B: