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yKpoI14uk [10]
3 years ago
11

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

Guy above deserves brainliest

Step-by-step explanation:

svp [43]3 years ago
7 0

Answer:

5sqrt(5) = q

-5sqrt(5) = q

Step-by-step explanation:

f(q) = q^2 -125

To find the roots set the equation equal to zero

0 = q^2 -125

Add 125 to each side

125 = q^2 -125+125

125 = q^2

Take the square root of each side

±sqrt(125) = sqrt(q^2)

±sqrt( 5*25) = q

±sqrt( 25)* sqrt(5) = q

±5* sqrt(5) = q

±5sqrt(5) = q

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sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

  • The range of the function is all real numbers less than or equal to 9.
<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

  • The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c  with the vertex \mathbf{(x_v,y_v)}

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The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

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Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

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