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yKpoI14uk [10]
3 years ago
11

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

Guy above deserves brainliest

Step-by-step explanation:

svp [43]3 years ago
7 0

Answer:

5sqrt(5) = q

-5sqrt(5) = q

Step-by-step explanation:

f(q) = q^2 -125

To find the roots set the equation equal to zero

0 = q^2 -125

Add 125 to each side

125 = q^2 -125+125

125 = q^2

Take the square root of each side

±sqrt(125) = sqrt(q^2)

±sqrt( 5*25) = q

±sqrt( 25)* sqrt(5) = q

±5* sqrt(5) = q

±5sqrt(5) = q

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The x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is (17, 11)

<h3>Midpoint of coordinate points</h3>

The midpoint of a line is the point that bisects or divides the line into two equal parts

If the line JK is partitioned into the ratio 1:4 with the following coordinates

J(-15, -5) and K(25, 15)

Using the expression below;

M(x, y) =[mx1+nx2/m+n, my1+ny2/m+n]

Substitute the ratio and the coordinates

M(x, y) =[1(-15)+4(25)/4+1, 1(-5)+4(15)/1+4]

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Hence the x- and y- coordinates of point E, which partitions the directed line segment from J to K into a ratio of 1:4 is ((17, 11)

Learn more on midpoint of a line here: brainly.com/question/5566419

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