3 years ago

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Mathematics

2 answers:

Elis [28]3 years ago

8 0

Answer:

Guy above deserves brainliest

Step-by-step explanation:

svp [43]3 years ago

7 0

Answer:

5sqrt(5) = q

-5sqrt(5) = q

Step-by-step explanation:

f(q) = q^2 -125

To find the roots set the equation equal to zero

0 = q^2 -125

Add 125 to each side

125 = q^2 -125+125

125 = q^2

Take the square root of each side

±sqrt(125) = sqrt(q^2)

±sqrt( 5*25) = q

±sqrt( 25)* sqrt(5) = q

±5* sqrt(5) = q

±5sqrt(5) = q

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X⁴+5x²-6=0 solve for x

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Let u = x², then we would have u² + 5u - 6 = 0

From here, we can factor it and get us (u-1)(u+6) = 0

So our solution for u is u = -6 or 1.

Now substitute u back to x².

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Since ±√(-6) is not real number, we ignore it.

Which leave us x = ±√1 = <span>±1

So our real solution is x = -1 or 1.</span>

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