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yKpoI14uk [10]
3 years ago
11

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

Guy above deserves brainliest

Step-by-step explanation:

svp [43]3 years ago
7 0

Answer:

5sqrt(5) = q

-5sqrt(5) = q

Step-by-step explanation:

f(q) = q^2 -125

To find the roots set the equation equal to zero

0 = q^2 -125

Add 125 to each side

125 = q^2 -125+125

125 = q^2

Take the square root of each side

±sqrt(125) = sqrt(q^2)

±sqrt( 5*25) = q

±sqrt( 25)* sqrt(5) = q

±5* sqrt(5) = q

±5sqrt(5) = q

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Now put the values into formula :

43000 = A[\frac{1+(\frac{0.09}{4})^{14}-1 }{(\frac{0.09}{4} )}]

43000=A(\frac{(1+0.0225)^{14}-1}{\frac{0.09}{4}})

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43000=A(\frac{0.365483427}{0.0225})

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A = \frac{43000}{16.243708}

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3 years ago
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Black_prince [1.1K]

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