9 would be answer. when you plug in the 9 to the equation you get 14=14 which is a true statement.
Y=80x+270
If you want to know how to do it just let me know
Answer:
24
Step-by-step explanation:
First do parenthesis:
3*(9+1)-6 -> 3*(10)-6
Then do multiplication:
3*(10)-6 -> (30)-6
Then complete it with subtraction:
(30)-6 -> (24)
So your answer would be 24!
PEMDAS= Parenthesis, Exponents, Multiplication, Division, Add, Subtract.
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Step-by-step explanation:
by adding :
e=_4
d=24.....
