B is greater than 1, so B>1
Answer:
Q1) D
Q2) C
Step-by-step explanation:
Q1)
y ∝ x
y = kx
Let x=-1,y=2
2 = k(-1)
k = -2
Q2)
directly (y=kx)
Let x=2,y=4
4 = k(2)
k = 2
y = 2x
inverse (y = k/x)
Let x=2,y = 4
4 = k/2
k = 8
xy = 8
The first thing to do is find the slope of the given line m = (y2-y1)/(x2-x1). We need to find the slope because it is required to find the slope of the perpendicular line.
m = (-7-5)/(5+11) = -12/16 = -3/4
Now we find the midpoint of the line, this is where the perpendicular bisector be. Using the Midpoint equation
M=((x1+x2)/2,(y1+y2)/2)
M=((-11+5)/2, (5-7)/2)
M=(-6/2, -2/2)
M=(-3,-1)
Now that we have the slope and midpoint we can find the perpendicular bisector. A line is perpendicular to another if, when you multiply their slopes together they equal -1. To do this we simply invert the numerator and denominator of our current slope and flip the sign from negative to positive.
So, -3/4 becomes positive 4/3 for our new line. So for our perpendicular line we now know two things, the slope and a point on it (the bisector point). To find the equation of the line we need to plug the known point and slope into the equation y = mx + b and solve for b.
-1 = 4/3(-3) + b
-1 = -4 + b
b = -1 + 4
b = 3
Now we can build our equation for our perpendicular line
y = 4/3x + 3
<span>a unique real solution
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Answer:
the last picture
Step-by-step explanation:
the one where the line hits the -3 mark on the y-axis
