Answer:
one sixth of 7.5 pounds is 1.25, so 7.5 minus the rotten 1.25 is 6.25.
Step-by-step explanation:
There are few things to answer for this problem. First how many gallon of lemonade are left? You had 15 gallons and it's 60% gone. That means that 40% is left. You have to figure out how much 40% of 15 is. You do that by multiplying 15 x 0.40. The answer is 6.
Next, how much ice tea did you make? You figure this out with the ration 3:4 which can also be written as the fraction 3/4. The lemonade is the three and you know you made 15 gallons of that. 15 is 3 x 5. If you multiply the 4 times 5 also you will find out how much iced tea you made - 20 gallons.
How many gallons of iced tea are left? You figure this out by multiplying the percent left - 48% (100 - 52) by 20 gallons. 20 x 0.48 = 9.6 gallons.
Answer:
138°
Step-by-step explanation:
∠YUV creates arc YV. Circle Z is made up of arc UV (84°) and arc YV. Solve for the measure of arc YV. (A circle equals 360°)
84° + x = 360°
arc YV = 276°
arc YV is formed from a secant and a tangent. Because of this ∠YUV is half of arc YV.
276° ÷ 2 = 138°
∠YUV = 138°
Answer:
D
Step-by-step explanation:
Sample space = {H1,H2, H3, H4, H5, H6 , T1, T2, T3, T4, T5, T6}
So, (H, 6) is an element in the sample space
Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴