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2 years ago

Using Matrices to find a co-linear missing point

Mathematics

1 answer:

baherus [9]2 years ago

5 0

Answer:

subject?

Step-by-step explanation:

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Please helppp me :( it’s c^4/c^3

ira [324]

Answer:

Step-by-step explanation:

Because $\frac{c}{c}$ is 1 the equation turns into...

$c^{4-3}$

which equals...

$c^{1}$

and $c^{1}$ is just c

7 0

2 years ago

Evaluate the expression. 5 x (-6 / -1 + -10)

kotykmax [81]

Answer:

-20

Step-by-step explanation:

$5 * (-6 / -1+ -10)$

According to PEMDAS, we need to do the math in the parentheses first.

$-6 / -1 + -10$

Applying PEMDAS to the inside of the parentheses, then we have to divide -6 by -1, where we would get 6.

$6 + -10$

Adding a negative is the same as subtracting, so adding negative 10 is the same as subtracting 10.

$6 - 10$

Subtracting, we get 6 - 10 = -4 and we're left with:

$5 * (-4)$

Multiplying, <u>our final answer is -20.</u>

Hope this helps!

8 0

2 years ago

Pls help being timed

Sloan [31]

He needs 9 hours

hope this helps

3 0

3 years ago

I really need help here I don’t know how to do this

sattari [20]

Answer:

Second box for Justifications: Subtraction Property of equality

Third box for steps: $\frac{2}{3} y=-6$

Fourth box for steps: $\frac{2}{3} y*\frac{3}{2} =-6*\frac{3}{2}$

Fourth box for Justifications: Multiplication Property of equality

Fifth box for steps: $y=-9$

7 0

3 years ago

PleAse help with this question

Black_prince [1.1K]

5 it 5 it 5 555555

Step-by-step explanation:

hope this helped

8 0

3 years ago