Refer to the diagram shown below.
Given:
m∠A = 19°
c = 15
By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835
cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828
Answer:
The lengths are 4.88, 14.18, and 15.00 (nearest hundredth)
Answer:
n<-1
Step-by-step explanation:
Distribute 5 and -5 into each parenthesis respectively: 40n+35<5-5n-15
Combine like terms: 40n+35<-5n-10
Add 5n to both sides: 45n+35<-10
Subtract 35 from both sides: 45n<-45
Divide both sides by 45: n<-1
Answer:
me name is cameron
Step-by-step explanation:
to get the equation of any straight line, all we need is two points from it, Check the picture below, let's use those two.

