2 years ago

The sum of three consecutive numbers is 72 what is the smallest of the numbers

Mathematics

1 answer:

mylen [45]2 years ago

6 0

Answer:

Step-by-step explanation:

Suppose,

the first number = x

the second number = x+1

the third number = x+1+1 = x+2

Question wise,

x+x+1+x+2 = 72

3x+3 = 72

3x = 72-3 = 69

x = 69/3 = 23

so the numbers are,

23,(23+1)=24 and (23+2)=25

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Komok [63]

Solve for r.

You want to get r by itself on one side on the equal sign.

bh + hr = 25

Subtract bh from both sides.

hr = 25 - bh

Divide h on both sides.

r = 25 - bh / h

The two h's cancel each other out.

r = 25 - b

Hope this helps!

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve for x ~

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