What is the median of the data in this stem-and-leaf plot? 21 22 23 24

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

5 0

the median is 22.5 because 22.5 is in the middle of 22 and 23

ololo11 [35]3 years ago

4 0

The median is the middle number within a sequence of numbers listed from least to greatest.
21, 22, 23, 24.
An easy way to find the median is to cross out the smallest number and the biggest number. Keep doing this until you can no longer do it.
21 and 24 get crossed out, now we are left with 22 and 23.
Cross out 22 and 23.
If there are no numbers left, average the last 2 numbers you crossed out.
22 + 23 = 45
45/2 = 22.5
22.5 is your median.

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The question is incomplete. Here is the complete question.

Semicircles and quarter circles are types of arc lengths. Recall that an arc is simply part of a circle. we learned about the degree measure of an ac, but they also have physical lengths.

a) Determine the arc length to the nearest tenth of an inch.

b) Explain why the following proportion would solve for the length of AC below: $\frac{x}{12\pi } = \frac{130}{360}$

c) Solve the proportion in (b) to find the length of AC to the nearest tenth of an inch.

Note: The image in the attachment shows the arc to solve this question.

Answer: a) 9.4 in

c) x = 13.6 in

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a) $\frac{arclength}{2\pi.r } = \frac{mAB}{360}$ , where:

r is the radius of the circumference

mAB is the angle of the arc

arc length = $\frac{mAB.2.\pi.r }{360}$

arc length = $\frac{90.2.3.14.6}{360}$

arc length = 9.4

The arc lenght for the image is 9.4 inches.

b) An arc length is a fraction of the circumference of a circle. To determine the arc length, the ratio of the length of an arc to the circumference is equal to the ratio of the measure of the arc to 360°. So, suppose the arc length is x, for the arc in (b):

$\frac{x}{2.6.\pi } = \frac{130}{360}$