Important: If you're discussing squares, please express "the square of x" as x^2 (not as x2).
Please note that your y=x^2+3 is NOT a line. I will assume (probably incorrectly!) that you meant y=2x+3. The slope of this line is 2, so the slope of any line perpendicular to y=2x+3 is -1/2.
Now use the point-slope equation of a straight line:
y-8 = (-1/2)(x-1) (answer)
Answer:
|x-4| +|y-5|=0
Step-by-step explanation:
There are many equations that will graph as the point (x, y) = (4, 5). One of them is ...
|x-4| +|y-5| = 0
First you need to know that the internal angles of a triangle always equals 180°. Therefore:
15+45= 90°
Then since the angles should equal 180, you do:
180-90=90
So the missing angle equals 90°
The longest side in the triangle is opposite to the largest angle of this triangle. If triangle is acute, then all angles are acute. Acute angle has cosine that is positive.
Use cosine theorem to determine the cosine of the largest angle:
where 
is the largest angle.
Then
Since 
then
Divide this inequality by 5:
Note that 
then the smallest possible whole-number value of x is 7.
Answer: correct choice is B
The answer is 1 1/6.
Hope it was helpful :)
