4. What is the experimental probability of spinning orange?
2 answers:
Answer:6/25
To get this you just add up all the spins which equals 50 so this then means 50 is your denominator
Then because it’s asking for the orange you need to look at the orange colom and it say 12 so this is then this is the numerator
So it would be 12/50 but you can make this smaller so you divide by 2 and get 6/25
Hope this helped!
To get this you just add up all the spins which equals 50 so this then means 50 is your denominator
Then because it’s asking for the orange you need to look at the orange colom and it say 12 so this is then this is the numerator
So it would be 12/50 but you can make this smaller so you divide by 2 and get 6/25
Hope this helped!
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Answer:
Step-by-step explanation:
Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is
Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore .
Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.
Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.
Symmetry: It is clear to see the graph of f(x) has no symmetry.
Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe for all x in the domain.
The function is however bounded below by 0: no value of x in the domain exists which satisfies .
Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)
Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: .
End behaviour: As . As
