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son4ous [18]
3 years ago
5

If triangle ABC is similar to triangle PQR, find the value of x and y.

Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

x = 9

y = 6

Step-by-step explanation:

ΔABC ~ ΔPQR

Therefore, corresponding sides of these similar triangles will be in the proportional.

\frac{AB}{PQ}=\frac{BC}{QR}= \frac{AC}{PR}

\frac{6}{x}= \frac{4}{y}= \frac{8}{12}

\frac{6}{x}= \frac{8}{12}

x = \frac{12\times 6}{8}

x = 9

Similarly, \frac{4}{y}= \frac{8}{12}

y = \frac{12\times 4}{8}

y = 6

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Answer:

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1 pk balloons (1 x 30 = 30 balloons)

Step-by-step explanation:

divide 30 by 5, = 6

buy 6 packs noisemakers and one pack of balloons

4 0
3 years ago
What’s the answer to 3x-8y
Kamila [148]

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Step-by-step explanation:

3 0
3 years ago
Simplify the expression using properties of exponents. 25a^-5b^-8/5a^4b
ivanzaharov [21]

Answer: The simplification is 5*a^{-9}*b^{-9}

Step-by-step explanation:

Here we need to use the property:

\frac{a^n}{a^m} = a^{n - m}

We have the expression:

\frac{25*a^{-5}*b^{-8}}{5*a^{4}*b}

We can separate it in parts with the same base, then we can rewrite this as:

\frac{25*a^{-5}*b^{-8}}{5*a^{4}*b} = \frac{25}{5} \frac{a^{-5}}{a^4} \frac{b^{-8}}{b}

Using the first property we can rewrite this as:

\frac{25}{5} \frac{a^{-5}}{a^4} \frac{b^{-8}}{b} = 5*a^{-5 - 4}*b^{-8 - 1} = 5*a^{-9}*b^{-9}

6 0
3 years ago
Find zeroes and multiplicity for y=(2x +3)(x -1)^2
muminat

Answer:

zeros : -3/2 , multiplicity = 1

1 , multiplicity = 2

Step-by-step explanation:

y=(2x +3)(x -1)^2

To find zeros we set each factor =0  and solve for x

2x+3 =0

subtract 3 on both sides

2x= -3

divide by 2 on both sides

x= -3/2

The exponent of (2x+3) is 1 so multiplicity =1

Now we set (x-1)^2 =0

take square root on both sides

x-1 =0

add 1 on both sides

x=1

For (x-1)^2  the exponent is 2

So multiplicity = 2


7 0
3 years ago
PLEASE HELP ASAP!!!!!!!!!!
andriy [413]

Answer:

It probably is a rhombus.

Step-by-step explanation:

6 0
3 years ago
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