All categories

2 years ago

Can someone plz help me!!!!!

Mathematics

1 answer:

WITCHER [35]2 years ago

7 0

Answer:

Step-by-step explanation:

angle 64, 66, and vrw= equal 180

vrw=-64-66+180

vrw=50

You might be interested in

Can some one help me find the area? The arrows are just answers that could be right.

docker41 [41]

Area of circle=Πrsquare
A=Πx5x5
A=78.5
Area of rect 10x9=90
Tsurface =168.5

3 0

2 years ago

Lily has walked 2 miles. Her goal is to 6 miles. Lily plans to reach her goal by walking 3 miles each hour h for the rest of her

suter [353]

Step-by-step explanation:

if she did that she would have walked 36 miles multipy all of the numbers and theres ur answer i think i am so tired so if its wrong i am sooo sorry i havent slept in two days.... hope u have a better day than mine

4 0

3 years ago

Please help f(x)=x^2+x-1 g(x)=-3x+12 Find g(f(x))

Alecsey [184]

Answer: -3x^2-3x+9

Step-by-step explanation:

-3(x^2+x-1)+12 = -3x^2-3x-3+12 = -3x^2-3x+9

7 0

2 years ago

Help due really soon

nadya68 [22]

Answer:

B.) y - 6 = -8/5(x + 2)

Step-by-step explanation:

Remember in order to find the slope intercept form on 2 points, you need these equations: $\frac{x_2 -x_1}{y_2 -y_1}$ and $y-y_1=m(x-x_1)$

To find the slope, you will need to use the first equation. In this case the equation will look like this: $\frac{(-2)-6}{3-(-2)}=-\frac{8}{5}$

Then use the second equation, plug in the numbers, and you will get B as your answer

5 0

2 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 +

timama [110]

Looks like your function is

$f(x)=\dfrac x{6x^2+1}$

Rewrite it as

$f(x)=\dfrac x{1-(-6x^2)}$

Recall that for $|x|$ , we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

If we replace $x$ with $-6x^2$ , we get

$f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}$

By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2$

Solving for $x$ gives the interval of convergence,

$|x|^2$

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

3 0

2 years ago