This is a cube root, so we look for factors of 162 which are perfect cubes.
Find the prime factors of 162:-
162 = 2 * 3 * 3 * 3* 3
27 = 3^3 is a perfect cube
162 = 6 * 27
so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3
so the simplest form is 3 ^3√6
Answer:
Standard form is another way to write slope-intercept form (as opposed to y=mx+b). It is written as Ax+By=C. You can also change slope-intercept form to standard form like this: Y=-3/2x+3. Next, you isolate the y-intercept(in this case it is 3) like this: Add 3/2x to each side of the equation to get this: 3/2x+y=3.
Step-by-step explanation:
Standard form is another way to write slope-intercept form (as opposed to y=mx+b). It is written as Ax+By=C. You can also change slope-intercept form to standard form like this: Y=-3/2x+3. Next, you isolate the y-intercept(in this case it is 3) like this: Add 3/2x to each side of the equation to get this: 3/2x+y=3.
You add all the numbers & divide it by how many numbers 8 +9+9+9+10+10