Question

Robert spun the fair spinner shown below 1,060 times,

Answer 1

Answer:

About 400 times

Step-by-step explanation:

Given

$n = 1060$

See attachment for spinner

Required

Determine the number of times an outcome of 1, 3 or 8 is expected

First, calculate the theoretical probability of 1, 3, or 8

This is calculated as:

$Pr = P(1) + P(3) + P(8)$

The spinner is divided into 8 equal segments and each outcome appears once.

So, we have:

$Pr = \frac{1}{8}+\frac{1}{8}+\frac{1}{8}$

Take LCM and add

$Pr = \frac{1+1+1}{8}$

$Pr = \frac{3}{8}$

So, the expected number of times (E) is:

$E = Pr * n$

$E = \frac{3}{8} * 1060$

$E = \frac{3* 1060}{8}$

$E = \frac{3180}{8}$

$E = 397.5$

Approximate

$E = 398$

This means about 400 times