Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Look at the slope in each equation. A neg. slope indicates that the function is decreasing. A pos. slope: increasing.
Answer:
(4, 0)
Step-by-step explanation:
The circumference of a circle is 
where <em>r</em> is the radius.
In this case, 
. Divide both sides of the equation by 
to get
The center of the circle is on the <em>x</em>-axis, so the intercepts are 5 units to the left of the center and 5 units to the right of the center. The two intercepts are (-1-5, 0) and (-1+5, 0). The point that is on the positive <em>x</em>-axis is (4, 0).
See attached image.
A trapezoid would work perfectly.
