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g100num [7]
3 years ago
5

I need help with this question pls

Mathematics
2 answers:
telo118 [61]3 years ago
7 0

Answer:

\frac{ {2}^{4 + 3} }{2^{5 + 4} }

\frac{ {2}^{7} }{2^{9} }

= 2^7-9

= 2^-2

Nitella [24]3 years ago
6 0

Answer:

<h2>2^-2</h2>

Step-by-step explanation:

2^(3-5)

=2^-2

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Tanmayi wants to raise $160 for a school fundraiser. She has raised $130 so far. How much more does she
ohaa [14]

Answer:

$30

Step-by-step explanation:

$160-$130=$30

3 0
3 years ago
Read 2 more answers
In right triangle ABC, ZC is a right angle, m ZA = 52, AC = 10.01, and AB = c.
nlexa [21]

Answer:

The measurement of AB is 16.25 units.

Step-by-step explanation:

In right triangle ABC, ∠C is a right angle, m∠A = 52° , AC = 10.01, and AB = c.

We need to find the measurement of AB.

∠C is a right angle, it means AB is hypotenuse.

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos A=\dfrac{AC}{AB}

\cos (52^\circ)=\dfrac{10.01}{c}

0.616=\dfrac{10.01}{c}

c=\dfrac{10.01}{0.616}

c=16.25

Hence, the measurement of AB is 16.25 units.

6 0
3 years ago
Use the graph of f(x) to find the solution to the equation f(x)=0
myrzilka [38]
The solution will be where the graph crosses the x-axis.

When a graph crosses the x-axis, the value of the function is 0. Just look at your graph and look at the x-values where the graph crosses the x-axis.
7 0
3 years ago
A group of students wanted to investigate the claim that the average number of text messages sent yesterday by
Likurg_2 [28]
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
7 0
3 years ago
Write an expression for the model. Find the sum. options: a) 2 + (–3); 1 b) –3 + 2; 5 c) 2 + 3; 5 d) 2 + (–3); –1
Dima020 [189]

Answer:

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

Step-by-step explanation:

When adding integers (positive and negative whole numbers), there are three cases:

  • Positive and positive increases and sum is positive. Ex. 4 + 6 = 10
  • Positive and negative where you subtract and take the sign of the larger number. Ex. 3 + -8 = -5 or -3 + 8 = 5
  • Negative and negative decrease and the sum if negative. Ex. -4 + -6 = -10.

Use these rules to simplify each expression.

a) 2 + (–3) = -1 not 1     FALSE

b) –3 + 2 = -1 not 5      FALSE

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

5 0
3 years ago
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