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Lisa [10]
3 years ago
5

Hi please help I'm not sure how to solve this

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

\sqrt{\sqrt{85^{2} } } - 6^{2}=\\\sqrt{85-36}=\\\sqrt{49}=7

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jo divides a rectangle into parts. each part is 1/4 the area of the whole rectagle. how many parys did ko divide the rectanhle i
meriva
Jo divided the rectangle into 4 parts if each part is 1/4 of the whole rectangle. 4 is the denominator which is the number of parts that has been divided.
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Point P is the midpoint of DE DP=3x +2 and DE =10X-12 What is the length of DP
ivolga24 [154]
<h3>Given</h3>

DP = 3x+2

DE = 10x-12

P is the midpoint of DE

<h3>Find</h3>

DP

<h3>Solution</h3>

If P is the midpoint, then PE = DP. The parts of a line segment add up to give the length of the entire line segment:

... DP + PE = DE

... DP + DP = DE . . . . . . use DP = PE

... 2(DP) = DE . . . . . . . . simplify

... 2(3x + 2) = 10x - 12 . . substitute the given in formation

... 16 = 4x . . . . . . . . . . . . add -6x +12

... 4 = x . . . . . . . . . . . . . . divide by the coefficient of x

The length of DP is 3×4 +2 = 14

<u>Check</u>

The length of DE is 10×4 - 12 = 28, which is 2 times the length of DP

7 0
3 years ago
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Factor the perfect square trinomial 25x^2-60x+36
zaharov [31]

Since it is a perfect square trinomial, it is of the form:

a^2x^2-2abx+b^2 which simplifies to (ax-b)^2

Therefore:

sqrt(a)=sqrt(25)=5

sqrt(b)=sqrt(36)=6

Plug in a and b:

(ax-b)^2

(5x-6)^2

Test to make sure it did fit the formula:

-2abx=-60   (where x is 1)

-2(5)(6)=-60

-2(30)=-60

-60=-60

Answer:

(5x-6)^2

4 0
3 years ago
The graphs below have the same shape. What is the equation<br> of the blue graph?
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It’s a bc i go over left and up one
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3 years ago
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The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

8 0
4 years ago
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