Answer:
see explanation
Step-by-step explanation:
A = πr² ← r is the radius and r =
d ← d is the diameter
Hence
π (
d)² = A, that is
= A ( multiply both sides by 4 )
d²π = 4A ( divide both sides by π )
d² =
( take the square root of both sides )
d = 
Answer:
36
Step-by-step explanation:
12 x 3 = 36
Answer:
1/4 -or- 4
Step-by-step explanation:
take the x-axis value 16 and divide by the other x-axis value, 4.
One of the factors is ( h - 7 ) that’s the answer
Answer:
Table C
Step-by-step explanation:
Given
Table A to D
Required
Which shows a proportional relationship
To do this, we make use of:

Where k is the constant of proportionality.
In table (A)
x = 2, y = 4



x = 4, y = 9



Both values of k are different. Hence, no proportional relationship
In table (B)
x = 3, y = 4



x = 9, y = 16



Both values of k are different. Hence, no proportional relationship
In table (C):
x = 4, y = 12



x = 5, y = 15



x = 6, y = 18



This shows a proportional relationship because all values of k are the same for this table