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3 years ago

1. A square lot has an area of 64x² square units. What is the length of each side with full solution

Mathematics

2 answers:

sergiy2304 [10]3 years ago

4 0

$\sqrt{64} = 8$

The area of the square can be expressed as

$area = {s}^{2}$

So to go back to the side length, you just need to find the square root of the area.

Delvig [45]3 years ago

3 0

Answer:

Step-by-step explanation:

Length x width= area

For an area of a square, all the sides have the same measurements. Therefore, the area is gotten by multiplying the length by itself which is trying to find the square of a number. The square root of 64cm² is 8 because 8 multiplied by 8 gives us 64. hope this helps!

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Calendario matematico la necesito ya porfa.

Murrr4er [49]

The common difference based on the sequence given is 15.

<h3>How to illustrate the sequence?</h3>

It should be noted that the sequence given Isa arithmetic sequence.

The common difference will be the second term minus the first term. This will be:

= 101 - 86

= 15

In conclusion, the difference is 15.

Learn more about sequence on:

brainly.com/question/6561461

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8 0

2 years ago

How do i solve things that dont make sense to me even though i do know but dont know

kirill [66]

Answer:

Just try to make it make sense to you.

Step-by-step explanation:

For instance, a + 1 = 5

a = 4

We know that we should switch the terms as when it comes to normal numbers ,10 + 1 = 11 , 10 = 11-1. Therefore, the only trick is not to memorise, but try to understand the logic behind it. Hope this helps in some way???

7 0

2 years ago

1.) Determine the type of solutions for the function (Picture 1)

NNADVOKAT [17]

Answer:

1) 2 nonreal complex roots

2) 1 Real Solution

3) 16

4) Reflected, narrower by a factor of 2/5, slides right 4 units and slides up 6 (units)

Step-by-step explanation:

1) The graph does not intercept the x-axis, therefore, there are no real solutions at the point y = 0

We get;

y = a·x² + b·x + c

At y = 6, x = -2

Therefore;

6 = a·(-2)² - 2·b + c = 4·a - 2·b + c

6 = 4·a - 2·b + c...(1)

At y = 8, x = 0

8 = a·(0)² + b·0 + c

∴ c = 8...(2)

Similarly, we have;

At y = 8, x = -4

8 = a·(-4)² - 4·b + c = 16·a - 4·b + 8

16·a - 4·b = 0

∴ b = 16·a/4 = 4·a

b = 4·a...(3)

From equation (1), (2) and (3), we have;

6 = 4·a - 2·b + c

∴ 6 = b - 2·b + 8 = -b + 8

6 - 8 = -b

∴ -b = -2

b = 2

b = 4·a

∴ a = b/4 = 2/4 = 1/2

The equation is therefor;

y = (1/2)·x² + 2·x + 8

Solving we get;

x = (-2 ± √(2² - 4 × (1/2) × 8))/(2 × (1/2))

x =( -2 ± √(-12))/1 = -2 ± √(-12)

Therefore, we have;

2 nonreal complex roots

2) Give that the graph of the function touches the x-axis once, we have;

1 Real Solution

3) The given function is f(x) = 2·x² + 8·x + 6

The general form of the quadratic function is f(x) = a·x² + b·x + c

Comparing, we have;

a = 2, b = 8, c = 6

The discriminant of the function, D = b² - 4·a·c, therefore, for the function, we have;

D = 8² - 4 × 2 × 6 = 16

The discriminant of the function, D = 16

4.) The given function is g(x) = (-2/5)·(x - 4)² + 6

The parent function of a quadratic equation is y = x²

A vertical translation is given by the following equation;

y = f(x) + b

A horizontal to the right by 'a' translation is given by an equation of the form; y = f(x - a)

A vertical reflection is given by an equation of the form; y = -f(x) = -x²

A narrowing is given by an equation of the form; y = b·f(x), where b < 1

Therefore, the transformations of g(x) from the parent function are;

g(x) is a reflection of the parent function, with the graph of g(x) being narrower by 2/5 than the graph of the parent function. The graph of g(x) is shifted right by 4 units and is then slides up by 6 units.

7 0

3 years ago

I need some one to help me!! Is (7, 0) a solution to the equation y = x − 7?

Marianna [84]

Answer:

Yes

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Coordinates (x, y)

Step-by-step explanation:

Step 1: Define

Identify

Point (7, 0)

Equation y = x - 7

Step 2: Find

Substitute in point [Equation]: 0 = 7 - 7
Subtract: 0 = 0

Since 0 = 0 is true, then it would be a solution to the equation.

3 0

3 years ago

When the full season tickets first went on sale,2,000 Full season tickets sold for Section N. Two weeks after the tickets first

slega [8]

Image showing the arena ticket prices is missing, so i have attached it.

Answer:

$10000 more money was spent when the tickets first went on sale than after the first 2 weeks

Step-by-step explanation:

We are told that when the full season tickets first went on sale, that 2000 full season tickets were sold for section N.

Now, from the area ticket prices table attached, we can see that full season tickets for Section N costs $20

Thus, amount of money spent when the tickets first went on sale = 2000 × 20 = $40000

We are told that 2 weeks after the tickets first went on sale, they sold 1500 tickets. Thus, amount spent after 2 weeks release = 1500 × 20 = $30000

Difference in amount spent at the beginning and after 2 weeks = $40000 - $30000 = $10000

Thus, $10000 more money was spent when the tickets first went on sale than after the first 2 weeks

6 0

3 years ago

1. A square lot has an area of 64x² square units. What is the length of each side with full solution​

1. A square lot has an area of 64x² square units. What is the length of each side with full solution