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Trava [24]
2 years ago
6

Th earth is approximately 6,000,000,000,000,000,000,000,000 kilograms

Mathematics
2 answers:
arlik [135]2 years ago
5 0
6,000,000,000,000,000,000,000,000 kg  = 6 × 10^24 kg (2sf)
stiks02 [169]2 years ago
4 0
The scientific notation is <span>6x10^24.</span>
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Helppp i need answer now will give points
Papessa [141]

Answer:

f(g(3)) = 3

Step-by-step explanation:

We are told to solve for f(g(3)). This is also saying f of g of 3.

To find f(g(3)), we need to plug 3 in for x in g(x), since it says g(3).

g(x) = 3(3) - 4

Solve.

= 9 - 4

g(x) = 5

Now, we plug that into f(x), because g(x) was placed inside f and replaces the x variable of f(x).

f(5) = 2(5) - 7

Solve.

= 10 - 7

f(5) = 3.

f(g(3)) = 3

#teamtrees #WAP (Water And Plant)

4 0
3 years ago
Mr. Cruz bought 9 3/5 kg of meat. He used 2 3/5 kg for adobo, 4 3/5 kg for menudo and the rest for afritada. How many kilograms
Ray Of Light [21]

Answer:

3 3/5

Step-by-step explanation:

5 0
2 years ago
What is the value of x in the solution to this system of equations? 3x = 2y + 14<br> y = -6x + 18​
zmey [24]
Use substitution
3x = 2(-6x + 18) + 14
3x = -12x + 36 + 14
3x = -12x + 50
15x = 50, x = 50/15 = 10/3
Solution: x = 10/3
4 0
2 years ago
Daniela is a stain glass artist; she created the window below for her living room. What is
OLga [1]
The window has a shape of a semi-circle (half of a circle).

We know the diameter d = 12 ft.

The area of a (complete) circle is given by the formula:
A = π × r²

The radius can be found by halving the diameter:
r = d ÷ 2
  = 12 ÷ 2
  = 6 ft

Therefore the area of the circle will be:
<span>A = π × r²
    = 3.14 × 6</span>²
    = <span>3.14 × 36
    = 113.04 ft²

And the area of the semi-circle:
A = </span><span>113.04 </span>÷ 2
   = 56.52 ft²

Hence, the area of the window will be 56.52 ft².
3 0
3 years ago
Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(
MAVERICK [17]

Answer:

If you center the series at x=1

T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)

Where R(x) is the error.

Step-by-step explanation:

From the information given we know that

f(x) = e^{2x^2}

f'(x) = 4x e^{2x^2}   (This comes from the chain rule )

f^{(2)}(x) = 4e^{2x^2} (4x^2+1)   (This comes from the chain rule and the product rule)

f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)  (This comes from the chain rule and the product rule)

If you center the series at x=1  then

T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)

Where R(x) is the error.

3 0
2 years ago
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