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Gnom [1K]
2 years ago
12

Someone who la help me no links ???

Mathematics
2 answers:
sammy [17]2 years ago
6 0

Answer:

24

Step-by-step explanation:

Nina [5.8K]2 years ago
6 0

Answer:

24

Step-by-step explanation:

y = 8x

substitute 3 for x

y = 8(3)

y = 24

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Rolling a Red and Yellow Dice
grandymaker [24]

Answer:

Option C 5/12 is correct option

Step-by-step explanation:

We have to find the probability that shows yellow dice has a larger value than the red dice.

Probability= total no of favorable outcomes / total no of outcomes

in our case, considering the data set, we have to find those pair where value of yellow die is greater than the red die. Where (1,2) represents 1 on the red die and 2 on the yellow die

(1,2) (1,3) (1,4) (1,5) (1,6)

     (2,3) (2,4) (2,5) (2,6)

              (3,4) (3,5) (3,6)

                       (4,5) (4,6)

                                (5,6)

These are the possibilities where yellow die has greater value than red die.

total no of favorable outcomes = 15

total no of outcomes = 36

probability that yellow die has greater value than red die = 15 / 36

                                                                                                = 5/ 12

Option C 5/12 is correct option

3 0
3 years ago
I just need help with number 2, thank you
alekssr [168]

It represents the thing the avadocate needs to be muiltiplied by

4 0
3 years ago
Is 3/4 greater or less than 1/4
Ivahew [28]
3/4 is greater than 1/4! Imagine a cake with four slices in it, would you rather eat one slice out of four or three slices out of four? Three slices out of four is more than just one slice, and the more the cake the better~ Hope this helps! c:
3 0
3 years ago
Read 2 more answers
use the discriminant to determine how many and what kind of solutions the quadratic equation x²-x=-1/4 has
pantera1 [17]

\bf x^2-x=-\cfrac{1}{4}\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{4}}{4x^2-4x=-1}\implies 4x^2-4x+1=0


\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{4}x^2\stackrel{\stackrel{b}{\downarrow }}{-4}x\stackrel{\stackrel{c}{\downarrow }}{+1} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} \boxed{0}&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ (-4)^2-4(4)(1)\implies 16-16\implies \boxed{0}

4 0
3 years ago
three sets of a sum of a s number and four are added to the sum of seven times the same number and thirteen
marta [7]
Whaaaaaaaaaaaaaaaaaaaaaaaaaat
3 0
3 years ago
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